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Edexcel IGCSE Mathematics (Higher) · Unit 1

Unit 1 — Number

Everything on tomorrow’s assessment in one page: the method notes for all five strands, then all 28 questions from your Year 10 Revision sheet with worked answers. Try each one first — the answer only appears when you click.

Recurring decimalsFractions & decimalsPercentages Simple & compound interestDegree of accuracy / bounds RatioDirect & inverse proportion

Revision notes — the five strands of Unit 1

1Recurring decimals → fractions

Dot notation: a dot over a digit means that digit repeats; dots over the first and last digit of a block mean the whole block repeats. 0.7 = 0.777…   0.45 = 0.454545…   2.165 = 2.165165165…

Instant rules: one 9 for each digit in the repeating block → 1 digit: 0.7 = 7/9  ·  2 digits: 0.45 = 45/99 = 5/11  ·  3 digits: 0.123 = 123/999 = 41/333
then add one 0 for each digit sitting after the point but before the block → 0.12 345… has block 345 and “12” in front, so the denominator is 999 then 00 = 99900, and the top is 12345 − 12 = 12333 → 12333/99900 = 4111/33300.
No digits in front → no 0s → that’s the plain “over 9 / 99 / 999” case.

Algebra method (use for any mixed decimal — this is the full-marks method):

  1. Let x = the decimal.
  2. Multiply by 10a so the repeating part starts straight after the point.
  3. Multiply by 10b so one whole repeating block sits before the point (b > a).
  4. Subtract the two equations — the repeating tails cancel.
  5. Solve for x and simplify.
0.4515151…    x = 0.4515151…   10x = 4.515151…   1000x = 451.515151…
             1000x − 10x = 990x = 447   →   x = 447/990 = 149/330

Traps: give the fraction in its simplest form; convert to a mixed number if the question says so; a rounded decimal scores zero.

2Percentages

Multipliers are the fastest route.

JobDo thisExample
Increase by r%× (1 + r/100)+37.4% → ×1.374
Decrease by r%× (1 − r/100)−16% → ×0.84
Percentage change(difference ÷ original) × 10070 → 98: 28/70 = 40%
Reverse (find original)final ÷ multiplier£420 after 20% off → 420 ÷ 0.8 = £525
Simple interest: interest = P × r × n  (same interest every year, on the original only)
Compound interest / depreciation: amount = P × (1 ± r)n  (interest earns interest)

Profit & loss are always a percentage of the cost price. “Sells at 80% above cost” means the selling price is 180% of cost; a further 25% off gives 180 × 0.75 = 135% → 35% profit.

Traps: round only at the end; “how much interest” is not the total in the account; VAT, deposits and “per year” rates all use the same multiplier idea.

3Degree of accuracy & bounds

Bounds = the value ± half the stated accuracy. Error interval: lower bound ≤ x < upper bound.

StatementLower boundUpper bound
105 cm (nearest cm)104.5105.5
4.2 (1 d.p.)4.154.25
0.08 (1 s.f.)0.0750.085
70 (1 s.f.)6575
40 (nearest 10)3545
Calculations: for the biggest answer use the biggest top and the smallest bottom (max: UB×UB, UB÷LB  |  min: LB×LB, LB÷UB).
For a sum, max uses both UBs and min uses both LBs. For a subtraction, max = UB − LB and min = LB − UB.

Truncation cuts off rather than rounds: 159 000 truncated to 3 s.f. lies in 159 000 ≤ x < 160 000.

“Suitable degree of accuracy”: work out both bounds, then quote the value at the accuracy where the bounds agree, and say so: “x = 4.2 to 1 d.p. as both bounds round to 4.2.”

4Ratio

Simplifying: divide every part by the HCF — and convert units first (2 km : 3400 m = 2000 : 3400 = 10 : 17). With algebra: 12a² : 8a = 3a : 2.

Sharing into a ratio: add the parts, 1 part = total ÷ number of parts, then multiply up.

The exam favourite: one part is given → find 1 part first, then scale.
children : adults = 2 : 3 with 80 children → 1 part = 40 → 120 adults.
If a difference is given, divide the difference by the difference in parts (7 : 9 with 40 more = 2 parts = 40 → 1 part = 20).

Checklist: find 1 part → work out exactly what is asked (other part / total / difference / money). Don’t stop at 1 part.

5Direct & inverse proportion

Always three steps: write the equation with k → find k from the given pair → substitute.

StatementEquationk =
y ∝ xy = kxy ÷ x
y ∝ x²y = kx²y ÷ x²
y ∝ x³y = kx³y ÷ x³
y ∝ √xy = k√xy ÷ √x
y ∝ 1/xy = k/xy × x
y ∝ 1/x²y = k/x²y × x²

Worked: y ∝ x² with y = 24 when x = 2 → k = 24/4 = 6 → y = 6x² → x = 4 gives y = 96.

“What happens when … is halved?” reason from the power: F ∝ 1/d², so halving d makes d² a quarter as big and F four times as big.

“Which relationship fits the table?” compute y ÷ x, y ÷ x², y ÷ x³, y ÷ √x (or y × x, y × x²) and pick the one that stays constant.

Unit 1 overview: Higher — decimals, fractions, percentages, degree of accuracy, ratio and proportion

What the unit covers

Higher tier, five strands: decimals, fractions, percentages, degree of accuracy and ratio & proportion.

Tonight’s order, highest marks per minute: bounds calculations → percentage multipliers (compound & reverse) → proportion (find k first) → recurring decimals.

Past-paper practice — 4 real exam questions on recurring decimals

Straight from the actual Edexcel IGCSE Mathematics A papers (spec 4MA1). Do them on paper with full working — these are the “show that” style where the algebra earns the marks. Printable questions-only version: practice.pdf (questions only, room to write)
P1

Show that 0.254 = 14/55

2 marks

2019 Paper 1H, Q15 · real past paper, spec 4MA1

Past paper question 1: Show that 0.254 = 14/55
Show answer & working
Front: 2 (1 digit) → 0  |  Block: 54 (2 digits) → 99 → denominator 990
Top: 254 − 2 = 252
x       = 0.25454…
100x    = 25.454…
100x − x = 99x = 25.2
x = 25.2/99 = 252/990 = 14/55   (÷18)
Mark scheme: M1 for two recurring decimals that subtract to a whole number or terminating decimal (25.2 or 252), A1 for completion to 14/55 — algebra must be shown.
P2

Show that 0.2813 = 557/1980

2 marks

2021 Paper 1H, Q16 · real past paper, spec 4MA1

Past paper question 2: Show that 0.2813 = 557/1980
Show answer & working
Dots over 1 and 3 → block = 13; in front = 28 → 0s: 00, 9s: 99 → denominator 9900
Top: 2813 − 28 = 2785
x        = 0.281313…
100x     = 28.1313…
10000x   = 2813.13…
10000x − 100x = 9900x = 2785
x = 2785/9900 = 557/1980   (÷5)
Mark scheme also accepts 1000x = 281.313… with 10x = 2.81313… → 990x = 278.5 → 557/1980 — it only needs two recurring decimals that subtract to a whole number or terminating decimal.
P3

0.4ẋ as a fraction, in terms of x

3 marks

2021 Oct Paper 1H, Q18 · real past paper, spec 4MA1

Past paper question 3: 0.4x as a fraction, in terms of x
Show answer & working
The dot is over the x only, so 0.4ẋ = 0.4xxxx… (only x repeats).
y       = 0.4xxxx…
10y     = 4.xxxx…
100y    = 4x.xxxx…        ← 4x here is the two-digit number 40 + x
100y − 10y = 90y = (40 + x) − 4 = 36 + x
y = (36 + x)/90
Check with x = 5: (36 + 5)/90 = 41/90 = 0.45555… = 0.45 ✓
Mark scheme: A1 (36 + x)/90 oe, dependent on two correct recurring-decimal expressions being subtracted; working required.
P4

Show that 0.612 = 101/165

2 marks

2025 Paper 1HR, Q16 · real past paper, spec 4MA1

Past paper question 4: Show that 0.612 = 101/165
Show answer & working
Dots over 1 and 2 → block = 12; in front = 6 → 0s: 0, 9s: 99 → denominator 990
Top: 612 − 6 = 606
x        = 0.6121212…
10x      = 6.121212…
1000x    = 612.121212…
1000x − 10x = 990x = 606
x = 606/990 = 101/165   (÷6)
Mark scheme: M1 for two recurring decimals that subtract to a whole number or terminating decimal (606), A1 for completion to 101/165 using algebra.

Question bank — 28 questions from the Year 10 Revision sheet

Work each one on paper first, then click to check.

Ratio

Simplify, share into a ratio, or use one known part to scale up.

Chocolates & fruit

Exam question: Chocolates & fruit
Show answer & working
(a) 24 : 16 : 8 — divide every part by 8 → 3 : 2 : 1
(b) apples : bananas = 2 : 3. Two parts = 14 apples, so 1 part = 7 → bananas = 3 × 7 = 21
Q5

Election votes

2 marks
Exam question: Election votes
Show answer & working
1500 : 9000 — divide both by 1500 → 1 : 6
Q10

Rugby ticket sales

4 marks
Exam question: Rugby ticket sales
Show answer & working
children : adults = 2 : 3, and 2 parts = 80 children → 1 part = 40 → 120 adults.
Child ticket = ¼ of £8 = £2.
Total = 120 × £8 + 80 × £2 = 960 + 160 = £1120
Q15

Three angles in a ratio

Exam question: Three angles in a ratio
Show answer & working
2 parts = 50° → 1 part = 25°.
Other angles = 3 × 25 = 75° and 5 × 25 = 125°
Q16

Languages course (4 schools)

Exam question: Languages course (4 schools)
Show answer & working
French : German = 1 : 3, and 3 parts = 21 German → 1 part = 7 → 7 French, so that school sent 28.
Each of the other 3 schools sent the same number → 28 × 4 = 112 students

Percentages

Multipliers do almost all of this unit: increase ×(1+r), decrease ×(1−r).

TV: sale price & percentage increase

Exam question: TV: sale price & percentage increase
Show answer & working
(a) decrease of 20% → multiplier 0.8: 260 × 0.8 = £208
(b) change = 98 − 70 = 28 → 28 ÷ 70 × 100 = 40%

Percentage decrease (weight & book)

Exam question: Percentage decrease (weight & book)
Show answer & working
Peter: (80 − 64) ÷ 80 × 100 = 16/80 × 100 = 20%
Book: (19.80 − 12.87) ÷ 19.80 × 100 = 6.93/19.80 × 100 = 35%
Percentage change is always ÷ the ORIGINAL value.
Q24

Shop profit in a sale

3 marks
Exam question: Shop profit in a sale
Show answer & working
Cost price = 100%. Normal selling price = 100 + 80 = 180% of cost.
Sale price = 180 × 0.75 = 135% of cost.
Profit = 135 − 100 = 35%
Q19

Bucket filled with water

4 marks
Exam question: Bucket filled with water
Show answer & working
Increase = 2100 − 800 = 1300 g.
1300 ÷ 800 × 100 = 162.5% → to 2 s.f. = 160%
Q6

Gym members

2 marks
Exam question: Gym members
Show answer & working
2500 × 0.7 = 1750 members
Q15

Increase 7900 by 37.4%

2 marks
Exam question: Increase 7900 by 37.4%
Show answer & working
Multiplier 1 + 0.374 = 1.374 → 7900 × 1.374 = 10 854.6
Q18

Sofa in a sale

3 marks
Exam question: Sofa in a sale
Show answer & working
16% reduction → multiplier 0.84: 1799 × 0.84 = £1511.16
Q20

Barry’s monthly money

3 marks
Exam question: Barry’s monthly money
Show answer & working
Spent = 30% + 12% = 42% → left = 58%.
1300 × 0.58 = £754 (rent £390 + bills £156 = £546 spent)

Recurring decimals

Shift with ×10n, subtract to kill the repeating tail, then simplify.

Q19

Convert 0.51 to a fraction

2 marks
Exam question: Convert 0.51 to a fraction
Show answer & working
The dot is over the 1, so only the 1 repeats: 0.51 = 0.511111…
x     = 0.51111…
10x   = 5.11111…
100x  = 51.11111…
100x − 10x = 90x = 46
x = 46/90 = 23/45
Q17(a)

Convert 0.7 to a fraction

2 marks
Exam question: Convert 0.7 to a fraction
Show answer & working
One repeating digit → put it over 9: 7/9 (check: 7 ÷ 9 = 0.777…)
Q12

Convert 0.4515151… to a fraction

3 marks
Exam question: Convert 0.4515151… to a fraction
Show answer & working
The block 51 repeats after the first digit, so shift by 10 and by 1000.
x     = 0.4515151…
10x   = 4.515151…
1000x = 451.515151…
1000x − 10x = 990x = 447
x = 447/990 = 149/330
Q16

Write 2.165 as a mixed number

3 marks
Exam question: Write 2.165 as a mixed number
Show answer & working
Dots over 6 and 5 → the block 165 repeats: 2.165165165…
x     = 2.165165165…
1000x = 2165.165165…
999x  = 2163
x = 2163/999 = 721/333 = 2 55/333

Direct & inverse proportion

Three steps every time: write y = k(…), find k, substitute.

y is directly proportional to x²

3 marks
Exam question: y is directly proportional to x²
Show answer & working
y = kx². 24 = k × 2² = 4k → k = 6 → y = 6x².
x = 4: y = 6 × 16 = 96

H varies directly to the cube of c

Exam question: H varies directly to the cube of c
Show answer & working
H = kc³. 40 = k × 2³ = 8k → k = 5.
(a) H = 5c³
(b) c = 5: H = 5 × 125 = 625
(c) H = 5000: c³ = 1000 → c = 10
Q6

Force inversely proportional to d²

3+1+1+1
Exam question: Force inversely proportional to d²
Show answer & working
F = k/d². 50 = k/2² = k/4 → k = 50 × 4 = 200.
(a) F = 200/d²
(b) d = 10: F = 200/100 = 2 N
(c) F = 8: d² = 200/8 = 25 → d = 5 cm
(d) d halved → d² becomes ¼ as big, so F becomes 4 times as large.

Complete the table (y ∝ √x)

4 marks
Exam question: Complete the table (y ∝ √x)
Show answer & working
y = k√x. The table pairs x = 16 with y = 9: k = 9/√16 = 9/4 = 2.25 → y = 2.25√x.
y = 54: √x = 54 ÷ 2.25 = 24 → x = 24² = 576

A inversely proportional to B

4 marks
Exam question: A inversely proportional to B
Show answer & working
A = k/B. 4 = k/36 → k = 144 → A = 144/B.
When B = A: A = 144/A → A² = 144 → A = 12 (positive numbers only).

C directly proportional to √y

3+1
Exam question: C directly proportional to √y
Show answer & working
C = k√y. 12.8 = k × √16 = 4k → k = 3.2.
(a) C = 3.2√y
(b) y = 400: C = 3.2 × 20 = 64

Degree of accuracy (bounds)

Bounds = value ± ½ of the stated accuracy. For calculations, big top / small bottom.

Table 105 cm to the nearest cm

1+1
Exam question: Table 105 cm to the nearest cm
Show answer & working
Half the accuracy = 0.5 cm.
(a) smallest = 105 − 0.5 = 104.5 cm
(b) largest = 105 + 0.5 = 105.5 cm
Error interval 104.5 ≤ L < 105.5
Q5

Clementines & sausages

3+2
Exam question: Clementines & sausages
Show answer & working
Clementines: heaviest clementine = 74.5 g, heaviest net = 20.5 g.
Maximum mass = 12 × 74.5 + 20.5 = 894 + 20.5 = 914.5 g
Sausages: each between 7.5 and 8.5 cm.
Least = 6 × 7.5 = 45 cm; greatest = 6 × 8.5 = 51 cm
Q17

Lower bound of w = m/t

3 marks
Exam question: Lower bound of w = m/t
Show answer & working
m = 4.2 (1 d.p.) → 4.15 ≤ m < 4.25
t = 0.08 (1 s.f.) → 0.075 ≤ t < 0.085
For the smallest quotient use the smallest top and the biggest bottom:
w = 4.15 ÷ 0.085 = 48.8235… = 48.8 (3 s.f.)
Q21

Lower bound of v = u + at

4 marks
Exam question: Lower bound of v = u + at
Show answer & working
u = 2.4 (2 s.f.) → LB 2.35  |  a = 12 (2 s.f.) → LB 11.5  |  t = 5 (1 s.f.) → LB 4.5
v = 2.35 + 11.5 × 4.5 = 2.35 + 51.75 = 54.15 m/s
For a lower bound of a sum, take every lower bound — but note the product at is minimised by using 11.5 × 4.5 (both lower).
Q16

Lower bound of 5c² − 2d³

3 marks
Exam question: Lower bound of 5c² − 2d³
Show answer & working
c = 70 (1 s.f.) → 65 ≤ c < 75  |  d = 12 (nearest whole) → 11.5 ≤ d < 12.5
Make the + part as small as possible and the − part as big as possible:
5 × 65² = 21 125  and  2 × 12.5³ = 3906.25
Lower bound = 21 125 − 3906.25 = 17 218.75